In this example, you will learn to find the sum of natural numbers using a recursive function.
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To understand this example, you should have the knowledge of the following C programming topics:
The positive numbers 1, 2, 3… are known as natural numbers. The program below takes a positive integer from the user and calculates the sum up to the given number.
Visit this page to find the sum of natural numbers using a loop.
Sum of Natural Numbers Using Recursion
#include
int addNumbers(int n);
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
printf("Sum = %d", addNumbers(num));
return 0;
}
int addNumbers(int n) {
if (n != 0)
return n + addNumbers(n - 1);
else
return n;
}
Output
Enter a positive integer: 20 Sum = 210
Suppose the user entered 20.
Initially, addNumbers()
is called from main()
with 20 passed as an argument.
The number 20 is added to the result of addNumbers(19)
.
In the next function call from addNumbers()
to addNumbers()
, 19 is passed which is added to the result of addNumbers(18)
. This process continues until n is equal to 0.
When n is equal to 0, there is no recursive call. This returns the sum of integers ultimately to the main()
function.