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C Program to Count Number of Digits in an Integer

In this example, you will learn to count the number of digits in an integer entered by the user.

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To understand this example, you should have the knowledge of the following C programming topics:


This program takes an integer from the user and calculates the number of digits. For example: If the user enters 2319, the output of the program will be 4.


Program to Count the Number of Digits

#include int main() { long long n; int count = 0; printf("Enter an integer: "); scanf("%lld", &n); // iterate until n becomes 0 // remove last digit from n in each iteration // increase count by 1 in each iteration while (n != 0) { n /= 10; // n = n/10 ++count; } printf("Number of digits: %d", count); }

Output

Enter an integer: 3452
Number of digits: 4

The integer entered by the user is stored in variable n. Then the while loop is iterated until the test expression n! = 0 is evaluated to 0 (false).

  • After the first iteration, the value of n will be 345 and the count is incremented to 1.
  • After the second iteration, the value of n will be 34 and the count is incremented to 2.
  • After the third iteration, the value of n will be 3 and the count is incremented to 3.
  • After the fourth iteration, the value of n will be 0 and the count is incremented to 4.
  • Then the test expression of the loop is evaluated to false and the loop terminates.
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